11x^2-7x-4=0

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Solution for 11x^2-7x-4=0 equation: 



11x^2-7x-4=0

a = 11; b = -7; c = -4;
Δ = b2-4ac
Δ = -72-4·11·(-4)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-15}{2*11}=\frac{-8}{22}
=-4/11
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+15}{2*11}=\frac{22}{22}
=1
$

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